diketahui suatu kerucut dengan volume 770 jika tinggi kerucut 15 cm. maka berapakah luas kerucut
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Vol = (1/3) × (22/7) × r² × t
770 = (1/3) × (22/7) × r² × 15
770 = (22/7) × r² × 5
770 = (110/7) × r²
770 × (7/110) = r²
7² = r²
7 = r
Luas = (22/7) × r × (r + s)
= (22/7) × 7 × (7 + √(15² + 7²))
= 22 × (7 + √274)
= 154 + 22√274
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