. jawablah pertanyaan berikut
3 sin x =0, 0<= x <= 360° =![]()
3 sin x =0, 0<= x <= 360° =
3 sin x = 0, 0≤x≤360°
pindahin 3 nya.
sin x = 0/3
sin x = 0
sin x = sin 0°
a = 0°
rumus mencari sudut sin:
x = a + k.360° dan x = (180°-a) + k.360°
x = 0° + k.360°
ambil k bebas asalkan nilai x nya memenuhi syarat.
k = 0, x = 0° + 0.360° = 0° ✓
k = 1, x = 0° + 1.360° = 360° ✓
k = 2, x = 0° + 2.360° = 720°×
x = (180°-a) + k.360°
x = 180°-0° + k.360°
ambil k bebas.
k = 0, x = 180° + 0.360° = 180°✓
k = 1, x = 180° + 1.360° = 540° ×
jadi, HP={0°,180°,360°}
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